Mathematical genius Adam Spencer is the author of a new book The Number Games. Spencer is sharing riddles designed to get your grey matter firing over the festive season.

A 13-year-old genius solved this riddle in one second. How long will it take you?

We have already featured a couple of pretty taxing problems from the 2016 International Singaporean Mathematics Competition. If you haven't attempted them yet, try them from the list below.

Can you figure out this pentagon puzzle?
The puzzle that will blow your mind
Are you smarter than a 10-year old?
Can you solve this key puzzle?


Now I'd hate to suggest it's only Singapore that produces these mentally murderous messes. Here's a brain-buster from the Mathcounts National Mathematics competition in the United States.

Mathcounts is best thought of as the maths version of a national spelling bee. Two hundred or so completely awesome young guns are brought together to answer tougher and tougher questions until the top 12 face each other in a speed maths battle to the death.

The 2017 competition was won by Luke Robitaille of Texas, a 13-year-old boy who took less than a second to answer this question.


In a barn, 100 chicks sit peacefully in a circle. Suddenly, each chick randomly pecks the chick immediately to its left or its right. Each chick pecks only once, and is not affected by which way its neighbours peck. What is the most likely number of unpecked chicks?

Now I stress I don't expect you to get it in less than a second, and little Luke has spent thousands of hours practising this sort of stuff, but see if you can find the answer. You might have a good long think about it, but then again you might just pluck it out of midair. … Get it … pluck! Ow.


Imagine you are one of the chickens in the circle. What are all the possible 'peckings' that could happen to you, including not getting pecked, and what are the odds of each of those 'peckings' happening? Run these odds out over the 100 chickens and what number of 'no pecks' do you get?


For every chicken, the odds of getting pecked from the right is 0.5 and the odds of not getting pecked from the right is 0.5. Obviously the odds are the same for getting pecked from the left. So the odds of getting 'double pecked' are 0.5 x 0.5 = 0.25. The odds of getting 'not pecked' are also 0.5 x 0.5 = 0.25. The odds of getting 'single pecked' are 0.5 (0.25 from the left plus 0.25 from the right). Across 100 chickens you'd expect 25 to remain unpecked — you'd also expect 25 to be double pecked and 50 to be pecked once only.

Adam Spencer's book The Number Games is available now from all good bookstores or visit Shipping not available to NZ.